(4b^2)^0=(4+0)(b^2+0)=4b

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Solution for (4b^2)^0=(4+0)(b^2+0)=4b equation: 



(4b^2)^0=(4+0)(b^2+0)=4b

We move all terms to the left:

(4b^2)^0-((4+0)(b^2+0))=0

We add all the numbers together, and all the variables

4b^2^0-(4(b^2+0))=0



We calculate terms in parentheses: -(4(b^2+0)), so:

4(b^2+0)

We multiply parentheses

4b^2+0

We add all the numbers together, and all the variables

4b^2

Back to the equation:

-(4b^2)



We add all the numbers together, and all the variables

-4b^2+4b^2^0=0

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